{"id":692,"date":"2020-09-10T02:02:28","date_gmt":"2020-09-10T02:02:28","guid":{"rendered":"http:\/\/themindpalace.in\/?p=692"},"modified":"2021-08-28T09:40:58","modified_gmt":"2021-08-28T09:40:58","slug":"perimeter-and-area-of-simple-geometrical-figure","status":"publish","type":"post","link":"https:\/\/themindpalace.in\/index.php\/2020\/09\/10\/perimeter-and-area-of-simple-geometrical-figure\/","title":{"rendered":"PERIMETER AND AREA OF SIMPLE GEOMETRICAL FIGURE"},"content":{"rendered":"\n

Summary of perimeter and area of simple geometrical figure<\/a><\/p>\n\n\n\n

Solved exercise of perimeter and area of simple geometrical figure <\/a><\/p>\n\n\n\n

\"\"
perimeter <\/figcaption><\/figure>\n\n\n\n

Summary<\/h1>\n\n\n\n

The sum of length of all the sides of a geometrical figure is called its perimeter.<\/p>\n\n\n\n

Example: Planning the construction of a house. Since you have to pour a concrete foundation, within the housing constraints you want to maximize the area within the constraints which are related to the perimeter (like you can only get so close to a neighbor’s house, etc.)<\/p>\n\n\n\n

\"\"
concrete foundation<\/figcaption><\/figure><\/div>\n\n\n\n

Perimeter of simple geometrical figures<\/span><\/h4>\n\n\n\n

Some simple geometrical figures are<\/p>\n\n\n\n

\"\"
Geometrical figure<\/figcaption><\/figure><\/div>\n\n\n\n

Exercises 1.1<\/span><\/strong><\/h1>\n\n\n\n

Find the perimeter of the Geometrical figures<\/strong>.<\/span><\/p>\n\n\n\n

\"\"<\/figure><\/div>\n\n\n\n
GIVEN EF=3CM, FG=5CM ,GH=7CM ,HI=5CM ,IE=4CM                  
  Perimeter =  EF+  FG+ GH+ HI+ IE                    
  3CM+5CM+7CM+5CM+4CM <\/strong><\/span>                            
   Perimeter=24CM<\/span><\/strong><\/td><\/tr><\/tbody><\/table>

<\/figcaption><\/figure>\n\n\n\n
\"\"<\/figure><\/div>\n\n\n\n
GIVEN JK8C, JN=2CM,KL=6CM, MN-5CM ML 6CM                    
 Perimeter= JK+ JN +KL+MN +ML                   
  8CM + 2CM+ 6CM+ 5CM+ 6CM<\/strong><\/span>
Perimeter=27 cm<\/strong><\/span><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

                            <\/p>\n\n\n\n

\"\"<\/figure><\/div>\n\n\n\n
Given PQ=4CM,QR=2CM,RS=2CM,ST=4CM,TU=3CM,PU=3CM                  
    Perimeter= PQ+QR+RS+ST+TUPU                     
4CM+2CM=2CM+4CM+3CM+3CM  <\/strong><\/span>                           
Perimeter =  18CM<\/span><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
\"\"<\/figure><\/div>\n\n\n\n
GIVEN= 7CM, XC=8CM, NC=4CM, RN=6CM, MR=3C MW=2CM                  
Perimeter= WX+XC+NC+RN+MR+MW                    
7cm+8cm+4cm+6cm+3cm+2cm<\/strong><\/span>
      Perimeter =30CM.<\/span><\/strong>
<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

  II. In list ‘A’ plane figures and in list ‘B’ their perimeters are given. Match list ‘A’ with list ‘B’<\/span><\/strong><\/p>\n\n\n\n

\"\"<\/figure><\/div>\n\n\n\n

Exercise 1.2<\/span><\/strong><\/p>\n\n\n\n

\"\"<\/figure><\/div>\n\n\n\n

Perimeter( sum of 4 sides) = 24cm<\/p>\n\n\n\n

Sum of 3 sides        =22cm<\/p>\n\n\n\n

Length of the 4th<\/sup> side           =2cm<\/p>\n\n\n\n

Sum of given 3 sides          = 2cm+ 10cm+ 10cm<\/span><\/p>\n\n\n\n

       = 22cm<\/p>\n\n\n\n

Length and four side = perimeter – sum of 3 sides<\/p>\n\n\n\n

Length of 4th<\/sup> side =24cm -22cm     =       22cm<\/span>.<\/p>\n\n\n\n

2. <\/p>\n\n\n\n

\"\"<\/figure><\/div>\n\n\n\n

Perimeter (sum of 5 sides)=24cm<\/p>\n\n\n\n

=sum of 4 sides                     =19cm<\/p>\n\n\n\n

Length of the 5 sides           =5cm<\/p>\n\n\n\n

Sum of given 4 sides=3cm+ 4cm+ 4cm+ 8cm<\/span><\/p>\n\n\n\n

     =19cm<\/span><\/p>\n\n\n\n

Length and fifth side = perimeter-sum of 3 sides<\/p>\n\n\n\n

Length of 5 sides =24cm -19cm   =5cm<\/span>.<\/p>\n\n\n\n

3.<\/p>\n\n\n\n

\"\"<\/figure><\/div>\n\n\n\n

<\/p>\n\n\n\n

In general area is expressed in square unit. \u2234Units of Area : Sq cms, Sq mtrs, Sq kms\u2026 etc.<\/span><\/strong><\/p>\n\n\n\n

Example:<\/p>\n\n\n\n

Count the number of squares inside the shape. Totally there are 7 squares. Area of given shape = 7 sq cm.<\/p>\n\n\n\n

Exercise  1.3<\/span><\/strong><\/p>\n\n\n\n

On the graph sheet given, the area of each square is 1 sq cm. Find the area of the given shapes.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

There are totally 5 square.<\/p>\n\n\n\n

Area of given shape =5 sq cm<\/strong><\/span><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

There are totally 21 square<\/p>\n\n\n\n

Area of given shape=21 sq cm.<\/strong><\/span><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

There are totally 16 Square<\/p>\n\n\n\n

Area of given shape=16 sq cm.<\/strong><\/span><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

There are totally 20 Square<\/p>\n\n\n\n

Area of given shape=20 sq cm.<\/strong><\/span><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

There are totally 12 Square<\/p>\n\n\n\n

Area of given shape=12 sq cm.<\/strong><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Summary of perimeter and area of simple geometrical figure Solved exercise of perimeter and area of simple geometrical figure Summary The sum of length of all the sides of a geometrical figure is called...<\/p>\n","protected":false},"author":3,"featured_media":693,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[113,475,14],"tags":[91,92,90],"class_list":["post-692","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-4th-class-ncert-syllabus","category-posts-in-english","category-mathematics","tag-4th-class-maths","tag-4th-classncertmaths","tag-perimeter-area-of-simple-geometrical-figure"],"cp_meta_data":{"_edit_lock":["1630143658:2"],"_thumbnail_id":["693"],"_edit_last":["2"],"_layout":["inherit"],"_oembed_95287caaddeb112cd4edfcbd8e525566":["