PERIMETER AND AREA OF SIMPLE GEOMETRICAL FIGURE

Summary of perimeter and area of simple geometrical figure

Solved exercise of perimeter and area of simple geometrical figure

Summary

The sum of length of all the sides of a geometrical figure is called its perimeter.

Example: Planning the construction of a house. Since you have to pour a concrete foundation, within the housing constraints you want to maximize the area within the constraints which are related to the perimeter (like you can only get so close to a neighbor’s house, etc.)

Perimeter of simple geometrical figures

Some simple geometrical figures are

Exercises 1.1

Find the perimeter of the Geometrical figures.

II. In list ‘A’ plane figures and in list ‘B’ their perimeters are given. Match list ‘A’ with list ‘B’

Exercise 1.2

Perimeter( sum of 4 sides) = 24cm

Sum of 3 sides        =22cm

Length of the 4th side           =2cm

Sum of given 3 sides          = 2cm+ 10cm+ 10cm

= 22cm

Length and four side = perimeter – sum of 3 sides

Length of 4th side =24cm -22cm     =       22cm.

2.

Perimeter (sum of 5 sides)=24cm

=sum of 4 sides                     =19cm

Length of the 5 sides           =5cm

Sum of given 4 sides=3cm+ 4cm+ 4cm+ 8cm

=19cm

Length and fifth side = perimeter-sum of 3 sides

Length of 5 sides =24cm -19cm   =5cm.

3.

In general area is expressed in square unit. ∴Units of Area : Sq cms, Sq mtrs, Sq kms… etc.

Example:

Count the number of squares inside the shape. Totally there are 7 squares. Area of given shape = 7 sq cm.

Exercise  1.3

On the graph sheet given, the area of each square is 1 sq cm. Find the area of the given shapes.

There are totally 5 square.

Area of given shape =5 sq cm

There are totally 21 square

Area of given shape=21 sq cm.

There are totally 16 Square

Area of given shape=16 sq cm.

There are totally 20 Square

Area of given shape=20 sq cm.

There are totally 12 Square

Area of given shape=12 sq cm.

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